(1)/(2) H_(2(g)) + (1)/(2) Cl_(2(g)) rarr HCl_((g)) , Delta H^(0) = - 92.4 kJ/mole, HCl_((g)) + nH_(2)O rarr H_((aq))^(+) + Cl_((aq))^(-) , Delta H^(0) = -74.8 kJ/mole Delta H^(0)f for Cl_((aq))^(-) is

(1)/(2) H_(2(g)) + (1)/(2) Cl_(2(g)) rarr HCl_((g)) , Delta H^(0) = -

1.	(1)/(2) H_(2(g)) + (1)/(2) Cl_(2(g)) rarr HCl_((g)) , Delta H^(0) = - 92.4 kJ/mole, HCl_((g)) + nH_(2)O rarr H_((aq))^(+) + Cl_((aq))^(-) , Delta H^(0) = -74.8 kJ/mole Delta H^(0)f for Cl_((aq))^(-) is
Answer» <html><body><p>`-17.6` kJ/mole<br/>`-167.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` kJ/mole<br/>`+17.6` kJ/mole<br/>`-35.2` kJ/mole</p>Solution :`HCl_((<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)) + H_(2)O <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> H_((aq))^(+) + Cl_((aq))^(-)` <br/> `Delta H = Delta H_(f_(Cl^(-))) - Delta H_(f_(<a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>))` <br/> `-74.8 = Delta H_(f_(HCl)) - (-92.4) rArr Delta H_(f_(HCl)) = -167.2`</body></html>