(1)/(2)N_(2)(g)+O_(2)rarrNO_(2)(g),Delta_(r)H^(@)=-40KJ//mol Given: C_(P.m)(NO_(2),g)=40J//mol//K,C_(p,m) (O_(2),g)=30JK^(-1)mol^(-1) C_(P,m)N_(2)(g)=30JK^(-1)mol^(-1) What is the enthalpy of formation of NO_(2)(g) at 1298K ?

(1)/(2)N_(2)(g)+O_(2)rarrNO_(2)(g),Delta_(r)H^(@)=-40KJ//mol Given: C

1.	(1)/(2)N_(2)(g)+O_(2)rarrNO_(2)(g),Delta_(r)H^(@)=-40KJ//mol Given: C_(P.m)(NO_(2),g)=40J//mol//K,C_(p,m) (O_(2),g)=30JK^(-1)mol^(-1) C_(P,m)N_(2)(g)=30JK^(-1)mol^(-1) What is the enthalpy of formation of NO_(2)(g) at 1298K ?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`-40KJ//mol`<br/>`-50KJ//mol`<br/>`-45KJ//mol` <br/>`-6KJ//mol` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Delta_(r)H_(T)=Delta_(r)H^(@)+int_(298)^(1298)Delta_(r)C_(P)dT` <br/> At `1298KDelta_(r)H=-40KJ-5` <br/> `DeltaT=-40KJ-5xx1000xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)KJ=-45KJ//mol`</body></html>