1.

1/2. ""^nC_0 + ""^nC_1 + 2. ""^nC_2 + 2^2. ""^nC_3 + …….+ 2^(n-1) . ""^nC_n =

Answer»

`(3^(-N))/(2)`
`(4^(2n))/(2)`
`(4^n)/(2)`
`(3^n)/(2)`

Answer :D


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