InterviewSolution
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1). 20 lit/hr2). 18.59 lit/hr3). 17.42 lit/hr4). 21.17 lit/hr |
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Answer» Let the TOTAL capacity of a cistern be ‘m’ lit. Average RATE = total distance / time taken ⇒ Time taken by a PIPE to fill 1/3rd of a cistern = (m/3)/20 = m/60 HR ⇒ Time taken by a pipe to fill 1/5th of a cistern = (m/5)/24 = m/120 hr ⇒ REST part of a cistern remain to fill = m {1 - (1/3 + 1/5)} = m (1 - 8/15) ⇒ Rest part of a cistern remain to fill = 7m/15 ⇒ Time taken by a pipe to fill rest of cistern = (7m/15)/14 = m/30 hr Total time taken by a pipe to fill cistern completely = (m/60 + m/120 + m/30) hr = 7m/120hr Average rate to fill cistern completely: ⇒ Total capacity of a cistern / Total time taken by a pipe to fill cistern completely = m/(7m/120) = 120/7 = 17.14 lit/hr ∴ Average rate at which cistern will completely get filled is 17.14 lit/hr. |
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