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1.216 g of an organic compound was Kjeldahlised and the ammonia evolved was absorbed in 100 mL 1 N H_(2)SO_(4). The remaining acid solution was made upto 500 mL by addition of water. 20 mL of this dilute solution required 32mL of N/10 caustic soda solution for complete neutralisation. Calculate the percentage of nitrogen in the organic compound.

Answer» <html><body><p></p>Solution :20 mL of diluted unreacted `H_(2)SO_(4) -= 32 mL` of N/10 <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> solution<br/> `:.` 500 mL of diluted unreacted `H_(2)SO_(4) -= (32)/(20) xx 500 mL` of `(N)/(10) NaOH -= (32)/(20) xx (500)/(10)mL` 1N NaOH <br/> But 80 mL 1 N `NaOH -= 80 mL` of `1 N H_(2)SO_(4) :.`Acid left unused = 80 mL 1 `N H_(2)SO_(4)` <br/> or Acid used for <a href="https://interviewquestions.tuteehub.com/tag/neutralization-15018" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRALIZATION">NEUTRALIZATION</a> of `NH_(3) = (<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> - 80) = 20 mL 1 N H_(2)SO_(4)` <br/> `:. % N = (14 xx "<a href="https://interviewquestions.tuteehub.com/tag/normality-1124423" style="font-weight:bold;" target="_blank" title="Click to know more about NORMALITY">NORMALITY</a> of the acid" xx "Vol. of acid used")/("Mass of the substance taken") = (1.4 xx 1 xx 20)/(1.216) = 23.026`</body></html>


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