InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
1.216 g of an organic compound was Kjeldahlised and the ammonia evolved was absorbed in 100 mL 1 N `H_(2)SO_(4)`. The remaining acid solution was made upto 500 mL by addition of water. 20 mL of this dilute solution required 32mL of N/10 caustic soda solution for complete neutralisation. Calculate the percentage of nitrogen in the organic compound. |
|
Answer» 20 mL of diluted unreacted `H_(2)SO_(4) -= 32 mL` of N/10 NaOH solution `:.` 500 mL of diluted unreacted `H_(2)SO_(4) -= (32)/(20) xx 500 mL` of `(N)/(10) NaOH -= (32)/(20) xx (500)/(10)mL` 1N NaOH But 80 mL 1 N `NaOH -= 80 mL` of `1 N H_(2)SO_(4) :.`Acid left unused = 80 mL 1 `N H_(2)SO_(4)` or Acid used for neutralization of `NH_(3) = (100 - 80) = 20 mL 1 N H_(2)SO_(4)` `:. % N = (14 xx "Normality of the acid" xx "Vol. of acid used")/("Mass of the substance taken") = (1.4 xx 1 xx 20)/(1.216) = 23.026` |
|