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1.224g of a metallic carbonate on being strongly heated liberates 1309.28 mL of CO_(2) at 27^(@)C and 750 mm pressure of Hg. Find the equivalent mass of the metal carbonate. |
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Answer» SOLUTION :`("MASS of the metallic HYDROXIDE")/("mass of the metallic oxide")` `=("equivalent mass of the metallic hydroxide")/("equivalent mass of the metallic oxide")` or, `(1.872)/(1.224) =(E+17)/(E+8)""[therefore E=8""E_(OH^(-))=17,E_(O)=8]` |
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