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(1) 2n 3(ii) n2 +1 |
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Answer» i) put n = 1,2,3 first term is 2*(1)-3 = -1 2nd term is 2*(2)-3 = 1 3rd term is. 2*(3)-3 = 3 here Common difference is same for all the terms that is 1-(-1) = 2. so , it is an A.P ii) similarly for n²+1 first term is 2 second term is (2)²+1 = 53rd term is (3)²+1 = 10so, here Common difference is not same..5-1 = 4 but 10-5 = 5 , so it is not an A.P |
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