1^3+2^3+3^+___+n^3={n(n+1)/2}^2

1.	1^3+2^3+3^+___+n^3={n(n+1)/2}^2
Answer» step 1 : put n=1 p(1) = 1=1 step 2 : let the result true for n = kp(k) : 1^3 + 2^3 +_________+k^3 = {k(k+1)/2}^2 __(1)step3 : show the result is true for n=k+1 p(k+1) = 1^3+2^3+______+(k+2)

Discussion