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1). 31 ∶ 12). 19 ∶ 13). 19 ∶ 64). 31 ∶ 5 |
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Answer» Let x and y be 3a and 5a $( \RIGHTARROW \frac{{2x + 5y}}{{2Y - 3x}} = \frac{{2 \times 3a + 5 \times 5a}}{{2 \times 5a - 3 \times 3a}})$ $( \Rightarrow \frac{{2x + 5y}}{{2y - 3x}} = \frac{{6a + 25A}}{{10a - 9a}} = \frac{{31a}}{{1a}} = \;\frac{{31}}{1})$ |
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