1.

1). -32). -23). 44). 5

Answer»

Given that (x + a)is the HCF of 2x2 + 5x - 12 and x2 + x - 12

∴ Substitute x = - a in the any of the above equations, we get

⇒ 2 × (-a)2 + 5 × (-a) - 12 = 0

⇒ 2a2 - 5A - 12 = 0

⇒ 2a2 - 8a + 3A - 12 = 0

⇒ 2a (a - 4) + 3 (a - 4) = 0

⇒ (2a + 3) (a - 4) = 0

⇒ 2a + 3 = 0 and a - 4 = 0

⇒ a = - 3/2 and a = 4

∴ The VALUE of a is 4



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