InterviewSolution
Saved Bookmarks
| 1. |
1). -32). -23). 44). 5 |
|
Answer» Given that (x + a)is the HCF of 2x2 + 5x - 12 and x2 + x - 12 ∴ Substitute x = - a in the any of the above equations, we get ⇒ 2 × (-a)2 + 5 × (-a) - 12 = 0 ⇒ 2a2 - 5A - 12 = 0 ⇒ 2a2 - 8a + 3A - 12 = 0 ⇒ 2a (a - 4) + 3 (a - 4) = 0 ⇒ (2a + 3) (a - 4) = 0 ⇒ 2a + 3 = 0 and a - 4 = 0 ⇒ a = - 3/2 and a = 4 ∴ The VALUE of a is 4 |
|