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1). 42). 53). 64). 7 |
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Answer» Let the numbers be ‘a’, ‘B’, ‘c’ and ‘d’ Given, (a + b + c + d)/4 = 15 ⇒ a + b + c + d = 15 × 4 = 60----(1) Now, Average of a, b and c = 3 times d ⇒ (a + b + c)/3 = 3d ⇒ a + b + c = 9D----(2) Substituting EQUATION (2) in equation (1) ⇒ 9d + d = 60 ⇒ 10d = 60 ⇒ d = 60/10 = 6 ∴ Fourth number = d = 6 |
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