1.

1). 42). 53). 64). 7

Answer»

Let the numbers be ‘a’, ‘B’, ‘c’ and ‘d’

Given, (a + b + c + d)/4 = 15

⇒ a + b + c + d = 15 × 4 = 60----(1)

Now,

Average of a, b and c = 3 times d

⇒ (a + b + c)/3 = 3d

⇒ a + b + c = 9D----(2)

Substituting EQUATION (2) in equation (1)

⇒ 9d + d = 60

⇒ 10d = 60

⇒ d = 60/10 = 6

∴ Fourth number = d = 6



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