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1). 422). 283). 324). 36 |
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Answer» LET the numbers be x, x+2, x+4 and x+6 then: Formula: $(\eqalign{ & AVERAGE = {{SUM\ of\ elements} \over {number\ of\ elements}} \CR & Required\ average = {{x + x + 2 + x + 4 + x + 6} \over 4} \cr & \Rightarrow 29 = {{4x + 12} \over 4} \cr & \Rightarrow 29 = x + 3 \cr & \Rightarrow x = 26 \cr})$ Hence, the largest numbers = x+6 = 26 + 6 = 32 |
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