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1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of the incident photons produce photoelectrons, find the current in the cell.A. `0.59 muA`B. `1.16 muA`C. `0.48 muA`D. `0.79 muA` |
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Answer» Correct Answer - C `L^(0)=q/t=(Ne)/t=(plambdae)/(hc)` |
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