InterviewSolution
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1). 52). 33). 84). 2 |
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Answer» GIVEN p = $(\FRAC{{4{\rm{xy}}}}{{{\rm{x\;}} + {\rm{\;y}}}})$ $(\Rightarrow {\rm{\;}}\frac{{\rm{p}}}{{2{\rm{x}}}} = \frac{{2{\rm{y}}}}{{{\rm{x\;}} + {\rm{\;y}}}})$ and $(\frac{{\rm{p}}}{{2{\rm{y}}}} = \frac{{2{\rm{x}}}}{{{\rm{x\;}} + {\rm{\;y}}}})$. Applying COMPONENDO and dividendo on both, we get $(\Rightarrow {\rm{\;}}\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{x}}}}{{{\rm{p}} - 2{\rm{x}}}} = \frac{{2{\rm{y\;}} + {\rm{\;}}\left( {{\rm{x\;}} + {\rm{\;y}}} \RIGHT)}}{{2{\rm{y}} - \left( {{\rm{x\;}} + {\rm{\;y}}} \right)}})$ and $(\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{y}}}}{{{\rm{p}} - 2{\rm{y}}}} = \frac{{2{\rm{x\;}} + {\rm{\;}}\left( {{\rm{x\;}} + {\rm{\;y}}} \right)}}{{2{\rm{x}} - \left( {{\rm{x\;}} + {\rm{\;y}}} \right)}})$ $(\Rightarrow {\rm{\;}}\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{x}}}}{{{\rm{p}} - 2{\rm{x}}}} = \frac{{{\rm{x\;}} + {\rm{\;}}3{\rm{y}}}}{{{\rm{y}} - {\rm{x}}}})$ and $(\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{y}}}}{{{\rm{p}} - 2{\rm{y}}}} = \frac{{3{\rm{x\;}} + {\rm{\;y}}}}{{{\rm{x}} - {\rm{y}}}})$ $(\begin{array}{l}\therefore {\rm{\;}}\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{x}}}}{{{\rm{p}} - 2{\rm{x}}}}{\rm{\;}} + {\rm{\;}}\frac{{{\rm{p\;}} + {\rm{\;}}2{\rm{y}}}}{{{\rm{p}} - 2{\rm{y}}}} = \frac{{{\rm{x\;}} + {\rm{\;}}3{\rm{y}}}}{{{\rm{y}} - {\rm{x}}}}{\rm{\;}} + {\rm{\;}}\frac{{3{\rm{x\;}} + {\rm{\;y}}}}{{{\rm{x}} - {\rm{y}}}}\\ = \frac{{3{\rm{x\;}} + {\rm{\;y}}}}{{{\rm{x}} - {\rm{y}}}} - \frac{{{\rm{x\;}} + {\rm{\;}}3{\rm{y}}}}{{{\rm{x}} - {\rm{y}}}} = \frac{{\left( {3{\rm{x\;}} + {\rm{\;y}}} \right) - \left( {{\rm{x\;}} + {\rm{\;}}3{\rm{y}}} \right)}}{{{\rm{x}} - {\rm{y}}}}\\ = \frac{{2{\rm{x}} - 2{\rm{y}}}}{{{\rm{x}} - {\rm{y}}}} = \frac{{2\left( {{\rm{x}} - {\rm{y}}} \right)}}{{{\rm{x}} - {\rm{y}}}} = 2\end{array})$ |
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