

InterviewSolution
Saved Bookmarks
1. |
1^537 +i^539 + i^541 /i^534+ i^536+i^538 = |
Answer» i^537+i^539+i^541 =i.i^536+i.i^538+i.i^540 =i.(i^2)^268+i.(i^2)^269+i.(i^2)^270 =i.1+i.(-1)+i.1 [because (i^2)^even no.=1 and (i^2)^odd no.=-1] =i-i+i =i | |