1.

1.56xx10^(5) heat energy is transferred through wall 2 m^(2) and 12 cm thickness in every hour. Temperature difference between two walls is 20^(@)C, the mall conductivity of material of wall is. . . .. ."Wm"^(-1)K^(-1)

Answer»

`0.11`
`0.13`
`0.15`
`1.2`

SOLUTION :Here, `A="2 m"^(2)`
`L=12cm=0.12m`
`H=1.56xx10^(5)J`
`t=1" hour "=3600s`
`T_(1)-T_(2)=20^(@)C` or 20 K
Heat conducted in time .t. in thermal steady state,
`H=(kA(T_(1)-T_(2)))/(L)xxt`
`:.k=(HL)/(A(T_(1)-T_(2))xxt)`
`=(1.56xx10^(5)xx0.12)/(2xx20xx3600)`
`=0.0000013xx10^(5)`
`:.k=0.13" W m"^(-1)K^(-1)`


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