1). 6666.672). 3333.343). 5412.74). 4587.3

1.	1). 6666.672). 3333.343). 5412.74). 4587.3
Answer» LET assume part of 10,000 put under the interest rate of 8% = x Part of 10,000 put under the interest rate of 12% = y, x + y = 10,000 For part x, Interest = PRT/100, Where, P = Rs. x, R = 8%, T = 3 year Interest = (x × 8 × 3)/100 = 0.24x---- (1) For part y, Interest = PRT/100, Where, P = Rs. y R = 12%, T = 1 year Interest = (y × 12 × 1)/100 = 0.12y---- (2) COMPARING both equation, ⇒ 0.24x = 0.12y ⇒ x/y = 0.12/0.24 ⇒ x/y = 1/2 ⇒ 2x = y---- (3) Substitute the value of Eq(3), ⇒ x + 2x = 10000 ⇒ 3x = 10000 ⇒ x = Rs.3333.33 Put the value of x in Eq(3); ⇒ 2(3333.33) = y ∴ y = Rs. 6666.67

Answer»

LET assume part of 10,000 put under the interest rate of 8% = x

Part of 10,000 put under the interest rate of 12% = y,

x + y = 10,000

For part x,

Interest = PRT/100,

Where, P = Rs. x,

R = 8%,

T = 3 year

Interest = (x × 8 × 3)/100 = 0.24x---- (1)

For part y,

Interest = PRT/100,

Where, P = Rs. y

R = 12%,

T = 1 year

Interest = (y × 12 × 1)/100 = 0.12y---- (2)

COMPARING both equation,

⇒ 0.24x = 0.12y

⇒ x/y = 0.12/0.24

⇒ x/y = 1/2

⇒ 2x = y---- (3)

Substitute the value of Eq(3),

⇒ x + 2x = 10000

⇒ 3x = 10000

⇒ x = Rs.3333.33

Put the value of x in Eq(3);

⇒ 2(3333.33) = y

∴ y = Rs. 6666.67

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