1.

1.80 g of a certain metal burnt in oxygen gave 3.0 g of its oxide. 1.50 g of the same metal heated in steam gave 2.50 g of its oxide. Show that these results illustrate the law of constant proportion.

Answer»

Solution :In the first sample of the OXIDE,
WT. of metal=1.80 G, wt. of oxygen =(3.0-1.80)g =1.2 g
`therefore("wt. of metal")/("wt. of oxygen")=(1.80 g)/(1.2 g)=1.5`
In the SECOND sample of the oxide,
wt of metal =1.50 g, wt. of oxygen=(2.50-1.50)g =1 g
`therefore ("wt. of metal")/("wt. of oxygen")=(1.50g)/(1 g)=1.5`
Thus, in both samples of the oxide the proportions of the weights of the metal and oxygen are fixed. Hence, the results follows the law of constant proportion.
Note : This law is not applicable in CASE of isotopes.


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