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`(1)/(9x^(2)+6x+5)` |
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Answer» `int(1)/(9x^(2)+6x+5)dx` `=(1)/(9)int(1)/(x^(2)+(2)/(3)x+(5)/(9))dx` `=(1)/(9)int(1)/(x^(2)+(2x)/(3)+(1)/(9)+(5)/(9)-(1)/(9))dx` `=(1)/(9)int(1)/((x+(1)/(3))^(2)+((2)/(3))^(2))dx` `=(1)/(9).(1)/(2//3)tan^(-1)(x+(1)/(3))/((2)/(3))+c` `=(1)/(6)tan^(-1)((3x+1)/(2))+c` |
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