1.

∣∣∣∣∣1+a2−b22ab−2b2ab1−a2+b22a2b−2a1−a2−b2∣∣∣∣∣=(1+a2+b2)3

Answer»



1+a2b22ab2b2ab1a2+b22a2b2a1a2b2

=(1+a2+b2)3



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