1.

1 ampere current is equivalent toA. `6.25xx10^(-18)"electrons s"^(-1)`B. `2.25xx10^(-18)A"electrons s"^(-1)`C. `6.25xx10^(14)"electrons s"^(-1)`D. `2.25xx10^(14)"electrons s"^(-1)`

Answer» Correct Answer - A
`Q=It "also" Q="ne" [e=1.6xx10^(-19)C]`
`therefore =It or n=(It)/(e)=(1Axx1s)/(1.6xx10^(-19))`
`6.25xx10^(8)"electrons s"^(-1)`


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