(1) Arrange sp, sp^(2) & sp^(3) - orbitals in increasing order of : (a) bond length (b) bond angle ( c ) bond energy (d) size of orbitals and ( e ) s - character. (2) Organic compounds are usually water insoluble. Why? (3) Write the structure of the smallest hydrocarbon having empirical formula C_(2)H. What is the shape of the molecule? (4) Draw the p - orbitals involed in forming pi - bonds in the molecule, CH_(2) = C = CH_(2) and predict whether the molecule is planar or not.

(1) Arrange sp, sp^(2) & sp^(3) - orbitals in increasing order of : (

1.	(1) Arrange sp, sp^(2) & sp^(3) - orbitals in increasing order of : (a) bond length (b) bond angle ( c ) bond energy (d) size of orbitals and ( e ) s - character. (2) Organic compounds are usually water insoluble. Why? (3) Write the structure of the smallest hydrocarbon having empirical formula C_(2)H. What is the shape of the molecule? (4) Draw the p - orbitals involed in forming pi - bonds in the molecule, CH_(2) = C = CH_(2) and predict whether the molecule is planar or not.
Answer» Solution :(1) (a) `SP-spltsp^(2)-sp^(2)ltsp^(3)-sp^(3)` (b) `sp^(3)ltsp^(2)ltsp ( c ) )sp^(3)-sp^(3)ltsp^(2)-sp^(2)ltsp-sp` (d) `spltsp^(2)ltsp^(3)` ( E ) `sp^(3)ltsp^(2)ltsp` (2) Organic COMPOUNDS are covalent in nature. Thus they do not get ionised. Moreover, they are usually less polar ot non - polar compounds and hence do not dissolve in highly polar solvent, water. (3) The compound is `(C_(2)H)_(2) or C_(4)H_(2)` and its STRUTURE is `HC-=C-C-=CH`. The shape of the molecule is linear because all the C - atoms are sp - hybridised. (4) The molecule is non- planar because the two planes containing one C - atom and two H - atoms are perpendicular to each other.