1.

1). c/d2). d/c3). 14). 0

Answer»

GIVEN $(\frac{{3{\rm{a\;}} + {\rm{\;}}4{\rm{B}}}}{{3{\rm{c\;}} + {\rm{\;}}4{\rm{d}}}} = \frac{{3{\rm{a}} - 4{\rm{b}}}}{{3{\rm{c}} - 4{\rm{d}}}})$

$(\Rightarrow {\rm{\;}}\frac{{3{\rm{a\;}} + {\rm{\;}}4{\rm{b}}}}{{3{\rm{a}} - 4{\rm{b}}}} = \frac{{3{\rm{c\;}} + {\rm{\;}}4{\rm{d}}}}{{3{\rm{c}} - 4{\rm{d}}}})$ (By alternendo)

$(\Rightarrow {\rm{\;}}\frac{{\left( {3{\rm{a\;}} + {\rm{\;}}4{\rm{b}}} \RIGHT){\rm{\;}} + {\rm{\;}}\left( {3{\rm{a}} - 4{\rm{b}}} \right)}}{{\left( {3{\rm{a\;}} + {\rm{\;}}4{\rm{b}}} \right) - \left( {3{\rm{a}} - 4{\rm{b}}} \right)}} = \frac{{\left( {3{\rm{c\;}} + {\rm{\;}}4{\rm{d}}} \right){\rm{\;}} + {\rm{\;}}\left( {3{\rm{c}} - 4{\rm{d}}} \right)}}{{\left( {3{\rm{c\;}} + {\rm{\;}}4{\rm{d}}} \right) - \left( {3{\rm{c}} - 4{\rm{d}}} \right)}})$ (By componendo and dividendo)

$(\Rightarrow {\rm{\;}}\frac{{6{\rm{a}}}}{{8{\rm{b}}}} = \frac{{6{\rm{c}}}}{{8{\rm{d}}}})$ 

$( \Rightarrow {\rm{\;}}\frac{{\rm{a}}}{{\rm{b}}} = \frac{{\rm{c}}}{{\rm{d}}})$.



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