1.C,sin(240°+α(ii) cU(i)sin α + sin(120° + α)sin 8x cosin(A + B – InterviewSolution

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1.

1.C,sin(240°+α(ii) cU(i)sin α + sin(120° + α)sin 8x cosin(A + B

Answer»

sin(120+a) = sin120cos(a) +cos(120)sina = √3/2*(cosa) -1/2*(sina)

sin(240+a) = sin(240)cosa + cos(240)sina = -√3/2*cosa - 1/2sina

so, adding all the terms we get

=sina +√3/2*(cosa-cosa) -1/2*(sina+sina)=sina + 0-sina = 0

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