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1. Calculate the oxidation number of oxygen in OF2 and KO2 . 2. When Zn rod is dipped in blue CuSO4 solution ‘ the blue colour of CuSO4 fades due to displacement reaction. Write the reaction and identify the following: (i) The substance oxidised and the substance reduced. (ii) The oxidant and the reductant. |
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Answer» 1. OF2 : x + (-1 × 2) = 0 x – 2 = 0 x = +2 KO2 : (+1 × 1) + 2x = 0 1 + 2x = 0 2x = -1 x = – \(\frac{1}{2}\) 2. Zn(s) + CuSO4 (aq) → ZnSO4 (aq) + Cu(s) (i) Substance oxidised – Zn Substance reduced – Cu (ii) Oxidant-Cu Reductant – Zn |
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