1.

1. Calculate the oxidation number of oxygen in OF2 and KO2 . 2. When Zn rod is dipped in blue CuSO4 solution ‘ the blue colour of CuSO4 fades due to displacement reaction. Write the reaction and identify the following: (i) The substance oxidised and the substance reduced. (ii) The oxidant and the reductant.

Answer»

1. OF2 : x + (-1 × 2) = 0 

x – 2 = 0 

x = +2 

KO2 : (+1 × 1) + 2x = 0 

1 + 2x = 0

2x = -1 

x = – \(\frac{1}{2}\)

2. Zn(s) + CuSO4 (aq) → ZnSO4 (aq) + Cu(s)

(i) Substance oxidised – Zn 

Substance reduced – Cu 

(ii) Oxidant-Cu 

Reductant – Zn



Discussion

No Comment Found

Related InterviewSolutions