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1. Can the number 6", n being a natural number, end12010 (T-I)Iwith the digit 5? Give reasons |
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Answer» I think you're asking for 6^n.No, 6^n cannot end with five.For - "A ^ n"( where A is any integer ), to end with 5 ( or have 5 in unit place )."A"must be in the form of 2 ^ m X 5 ^ n .However, here 6 = 2 X 3ie. 6 cannot be written in the form of 2^m X 5^n.So, 6 ^n cannot end with five. And for, 6n.This too can't end with five, as all multiples of 6 end onlywith 0, 2,4, 6,8. |
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