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`1 cm` on the main scale of a vernier callipers is divided into `10 equal` parts. If `10` divisions of vernier coincide with `8` small divisions of main scale, then the least count of the calliper is.A. `0.01 cm`B. `0.02 cm`C. `0.05 cm`D. `0.005 cm` |
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Answer» Correct Answer - B `10VSD=8MSD` `1VSD=0.8MSD` Now `LC=1MSD-1VSD` `=1MSD-0.8MSD` `0.2MSD=0.2xx(1)/(10)cm` `=0.02cm`. |
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