1.

`(1)/(cos^(2)x(1-tanx)^(2))`

Answer» `int(1)/(cos^(2)x(1-tanx)^(2))dx`
माना `1-tanx=t`
`rArr -3 sec^(2)x dx = dt`
`rArr sec^(2)x dx = -dt`
`=int(sec^(2)x)/((1-tanx)^(2))dx=int-(dt)/(t^(2))`
`=(1)/(t)+c=(1)/(1-tanx)+c`


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