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`(1)/(cos^(2)x(1-tanx)^(2))` |
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Answer» `int(1)/(cos^(2)x(1-tanx)^(2))dx` माना `1-tanx=t` `rArr -3 sec^(2)x dx = dt` `rArr sec^(2)x dx = -dt` `=int(sec^(2)x)/((1-tanx)^(2))dx=int-(dt)/(t^(2))` `=(1)/(t)+c=(1)/(1-tanx)+c` |
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