1.

(1+costheta-isintheta)^(n)

Answer»

`2^ncos^n((THETA)/(2))CIS(ntheta)/(2)`
`2^ncos^n((theta)/(2))cis (-(ntheta)/(2))`
`2^nsin^n(theta/2) cis(ntheta)/(2)`
`2^nsin^n(theta/2)-cis(ntheta)/(2)`

ANSWER :B


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