InterviewSolution
`2^ncos^n((THETA)/(2))CIS(ntheta)/(2)``2^ncos^n((theta)/(2))cis (-(ntheta)/(2))``2^nsin^n(theta/2) cis(ntheta)/(2)``2^nsin^n(theta/2)-cis(ntheta)/(2)`
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