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1∫√e 3x2 (lnx)2 dx |
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Answer» I hope you are troubled only what should be done about the substitution, right ? Actually it's my first time answering so I actually wanted to upload the answer image but the insertion system troubles me. You can simply multiply and divide by 9. Put the 9 inside (lnx)² to get (lnx³)² Now substitute (Lnx³) = t with x³= e^t Then we can write 3x²dx = e^t dt. Don't forget to change the limits. Thus integral converts to (integral)(0 to 3/2) 1/9 × t²e^t dt Which can be solved easily by integration by parts. |
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