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1. Find the roots of the following quadratic equa(0) r-3x - 10=0 |
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Answer» x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=1 x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=0(x+5)(x+2)=0x+5= x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=1 x= -2 or 5 is the correct answer for this question 5,-2 is the correct answer of the given the correct value of x in this question is _2and 5 x^2-3x-10 = x^2-5x+2x-10=0; x(x-5)+2(x-5)=( x+2)(x-5)=0; x=-2; x=5 x^2-3x-10=0x^2-5x+2x-10=0x(x-5)+2(x-5)=0(x-5)(x+2)=0either x-5=0 , x= 5or x+2=0 ,x= -25, -2 are the zerosif a,b be zerossum of zerosa+b= -(-3)/1=3product of zerosa -10/1= -10 |
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