(1) For an A.P., if S10-150 and S,-126, t10=? – InterviewSolution

1.

(1) For an A.P., if S10-150 and S,-126, t10=?

Answer»

S=(n/2)(2a+(n-1)d)S10=5(2a+9d)150=5(2a+9d)150/5=30=(2a+9d)

30=(2a+9d).... (1)

S9=9/2(2a+8d)126=9/2(2a+8d)126*2/9=30=(2a+8d)28=2a+8d......(2)

Subtract 2 from 1

2=d

a=28-8d/2=28-16/2=12/2=6

t10=a+9d=6+9(2)=6+18=24

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