1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equivalent mass of the metal is :

1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equival

1.	1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equivalent mass of the metal is :
Answer» <html><body><p>25<br/>50<br/>20<br/>40</p>Solution :N//A</body></html>