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1 g of a mixture of `NaHCO_(3)` and `Na_(2)CO_(3)` is heated to `150^(@)C`. The volume of the `CO_(2)` produced at STP is 112.0 mL. Calculate the percentage of `Na_(2)CO_(3)` in the mixture `(Na=23, C=12, O=16)`A. 20B. 46C. 84D. 16 |
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Answer» Correct Answer - D `2NaHCO_(3) overset(150^(@)C)(rarr) Na_(2)CO_(3)+CO_(2)+H_(2)O` `n_(NaHCO_(3))/n_(CO_(2))=2/1` `n_(NaHCO_(3))=2n_(CO_(2))` `=2xx112/22400=0.01` mole `W_(NaHCO_(3))=0.01xx84=0.84 g` `W_(Na_(2)CO_(3))=1.00-0.84=0.16 g` `% Na_(2)CO_(3)=16`. |
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