1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas. The percentage of impurity in the sample is

1 g of an impure sample of magnesium carbonate (containing no thermall

1.	1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas. The percentage of impurity in the sample is
Answer» 0 0.044 0.16 0.084 Solution :`MgCO_(3) to MgO +CO_(2) UARR` `MgCO_(3): (1xx24) + (1xx12) + (3xx16)=84g` 100% PURE 84 g of `MgCO_(3)` on heating gives 44g `CO_(2)` Given that 1g of `MgCO_(3)` on heating gives 0.44g `CO_(2)` Therefore, 854 g `MgCO_(3)` SAMPLE on heating gives 36.96 g `CO_(2)` Percantaqge of PURITY of the sample= `(100%)/(44 g CO_(2)) xx36.96g CO_(2)` =84% Percentage of impurity=16%