1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas. The percentage of impurity in the sample is

1 g of an impure sample of magnesium carbonate (containing no thermall

1.	1 g of an impure sample of magnesium carbonate (containing no thermally decomposable impurities) on complete thermal decomposition gave 0.44 g of carbon dioxide gas. The percentage of impurity in the sample is
Answer» <html><body><p>0<br/>0.044<br/>0.16<br/>0.084</p>Solution :`MgCO_(3) to MgO +CO_(2) <a href="https://interviewquestions.tuteehub.com/tag/uarr-3241817" style="font-weight:bold;" target="_blank" title="Click to know more about UARR">UARR</a>` <br/>`MgCO_(3): (1xx24) + (1xx12) + (3xx16)=84g` <br/><a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>% <a href="https://interviewquestions.tuteehub.com/tag/pure-1172806" style="font-weight:bold;" target="_blank" title="Click to know more about PURE">PURE</a> 84 g of `MgCO_(3)` on heating gives 44g `CO_(2)` <br/>Given that 1g of `MgCO_(3)` on heating gives 0.44g `CO_(2)` <br/>Therefore, 854 g `MgCO_(3)` <a href="https://interviewquestions.tuteehub.com/tag/sample-1194587" style="font-weight:bold;" target="_blank" title="Click to know more about SAMPLE">SAMPLE</a> on heating gives 36.96 g `CO_(2)` <br/>Percantaqge of <a href="https://interviewquestions.tuteehub.com/tag/purity-609119" style="font-weight:bold;" target="_blank" title="Click to know more about PURITY">PURITY</a> of the sample= `(100%)/(44 g CO_(2)) xx36.96g CO_(2)` <br/>=84% <br/>Percentage of impurity=16%</body></html>