1.

1 g of Mg is burnt in a closed vessel containing 0.5 g of O_(2). Which of the following statements is correct ?

Answer»

`O_(2)` is the limiting REAGENT and Mg is in excess by 0.25 g
Mg is the limiting reagent and is in excess by 0.5 g
`O_(2)` is the limiting reagent and is in excess by 0.25 g
`O_(2)` is the limiting reagent and Mg is in excess by 0.75 g

Solution :`underset(2xx24)(2Mg)+underset(2xx16)(O_(2))rarr2MgO`
48 g of Mg require `O_(2)=32` g
1g of Mg require `O_(2)=(32)/(48) = 0.66 g`
`O_(2)` actually AVAILABLE = 0.5 g
This MEANS that `O_(2)` is the limiting reactant
0.5 g of `O_(2)` will react with `Mg = (48)/(32) XX 0,5 = 0.75 g`
Excess of `Mg = 1 -0.75 =0.25 g`.


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