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1 gm steam at 100° can melt how much ice at 0°CA) 80/540 gmB) 540/80 gmC) 8 gmD) 8 kg |
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Answer» The correct option is (D) 8 kg Suppose m gm ice melted, then heat required for its melting = mL = m × 80 cal. Heat available with steam for being condensed and then brought to 0∘C. = 1 × 540 + 1 × 1 × (100 − 0) = 640 cal ⇒ heat lost = heat taken ⇒ 640 = m × 80 ⇒ m = 8 gm. |
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