1 gram hydrogen is present in 0.0833 mole carbohydrate. The empirical formula of carbohydrate is CH_(2)O. What will be the molecular formula ?

1 gram hydrogen is present in 0.0833 mole carbohydrate. The empirical

1.	1 gram hydrogen is present in 0.0833 mole carbohydrate. The empirical formula of carbohydrate is CH_(2)O. What will be the molecular formula ?
Answer» `C_(5)H_(10)O_(5)` `C_(3)H_(4)O_(3)` `C_(12)H_(22)O_(11)` `C_(6)H_(12)O_(6)` Solution :In 0.0833 mole carbohydrate1 gm hydrogen is present . `:.` In 1 mole `=(1xx1)/(0.0833)=12` gm hydrogen The number of H atoms `= 12/1 = 12` MOLECULAR formula `=C_(6)H_(12)O_(6)`