1 grams of a carbonate (M_(2)CO_(3))on tratment with excess HCl produces 0.01186 mole of CO_(2). The molar mass of M_(2)CO_(3)in gmol^(-1) is .....

1 grams of a carbonate (M_(2)CO_(3))on tratment with excess HCl produc

1.	1 grams of a carbonate (M_(2)CO_(3))on tratment with excess HCl produces 0.01186 mole of CO_(2). The molar mass of M_(2)CO_(3)in gmol^(-1) is .....
Answer» 1186 84.3 118.6 11.86 Solution :`M_(2)CO_(3) + 2HCl rarr MCl_(2) + H_(2)O + CO_(2)` `(1)/(M_(0))` MOLE `rarr ""0.01186 ` mole where , `M_(0) = ` MOLECULAR mass of `M_(2)CO_(3)` `(1)/(M_(0))= 0.01186` `:.M_(0)=84.3` gram/mole