1.how many years, a sum of money amount to double of itself at 10% pa.

1.	1.how many years, a sum of money amount to double of itself at 10% pa.?
Answer» If the sum of money doubles itself in 10 years, then the number of years it would triple itself is 15 years. It is based on a simple logic. You can consider the sum as 1000. After 10 years it would be 2000. After 15 years, the sum would be 3000 thousand. Hence, the answer to this question is 15 years. let money be rs. 100r=10% t=?p=100 rs. i=rs. 100i=(p×r×t)/100100=(100×10×t)/100t=100/10t=10 years. ans.

1.how many years, a sum of money amount to double of itself at 10% pa.?

Answer»

If the sum of money doubles itself in 10 years, then the number of years it would triple itself is 15 years. It is based on a simple logic.

You can consider the sum as 1000. After 10 years it would be 2000.

After 15 years, the sum would be 3000 thousand. Hence, the answer to this question is 15 years.

let money be rs. 100r=10% t=?p=100 rs. i=rs. 100i=(p×r×t)/100100=(100×10×t)/100t=100/10t=10 years. ans.