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1(i) 7991207481have to be divided into planks of the29. Three pieces of timber, 42-m. 49-m and 63-m long, have to be divided insame length. What is the greatest possible length of each plank?nin 1031 4341 and 465 1. of milk respectively. Find the capacitytimes |
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Answer» The lengths of the three pieces of timber are 42 m, 49 m and 63 m.The greatest possible length of each plank will be given by the HCF of 42, 49 and 63. Firstly, we will find the HCF of 42 and 49 by division method. ∴The HCF of 42 and 49 is 7.Now, we will find the HCF of 7 and 63.∴The HCF of 7 and 63 is 7.Therefore, HCF of all three numbers is 7Hence, the greatest possible length of each plank is 7 m. |
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