1.

1-i in square root

Answer» 1-i = (x+iy)^21-i = x- (iy)^2= x^2- y^2+ 2xyix^2- y^2 = 1 and 2xy = -1(x^2+y^2)^2 = (x^2- y^2)^2 + (2xy)^2(x^2+ y^2)^2 =1 - 1 =0


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