1 + i2 + i4 + i6 + ... + i2n is(A) positive (B) negative(C) 0 (D) ca – InterviewSolution

1.

1 + i2 + i4 + i6 + ... + i2n is(A) positive (B) negative(C) 0 (D) can not be evaluated

Answer»

Answer is (D),

1 + i² + i⁴ + i⁶ + ... + i²ⁿ = 1 – 1 + 1 – 1 + ... (–1)ⁿ which can not be evaluated unless n is known.

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