1. Ia point N(o, 2) is equidistant from the points B(31. Ifa point A(0

1.	1. Ia point N(o, 2) is equidistant from the points B(31. Ifa point A(0, 2) is equidistant from the points B(3, p) and Clp, 5), find the valuc of p. [2Mj
Answer» Given, AB=AC = whole root of (0-3)^2 + (2-p)^2 = whole root of (0-p)^2 + (2-5)^2 = 9 + (2-p)^2 = p^2 + 9 = 4 + p^2 - 4p = p^2 4p =4 p = 1. Substitute of p-value in AB Length of AB = whole root of (0-3)^2 + (2-1)^2 = whole root of 9 + 1 = root 10.

1. Ia point N(o, 2) is equidistant from the points B(31. Ifa point A(0, 2) is equidistant from the points B(3, p) and Clp, 5), find the valuc of p. [2Mj

Answer»

Given, AB=AC

= whole root of (0-3)^2 + (2-p)^2 = whole root of (0-p)^2 + (2-5)^2

= 9 + (2-p)^2 = p^2 + 9

= 4 + p^2 - 4p = p^2

4p =4

p = 1.

Substitute of p-value in AB

Length of AB = whole root of (0-3)^2 + (2-1)^2

= whole root of 9 + 1

= root 10.