InterviewSolution
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1). If Quantity 1 is maximum2). If Quantity 2 is maximum3). If Quantity 3 is maximum4). If Quantity 1 = Quantity 2 = Quantity 3 or relation can’t be established |
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Answer» Quantity 1: Let the sum be RS. 100. Then, ⇒ S.I. for first six MONTHS = [(100 × 10 × 1)/100 × 2] = Rs. 5 ⇒ S.I. for NEXT six months = [(105 × 10 × 1)/100 × 2] = Rs. 5.25 ⇒ So, amount at the end of 1 YEAR = Rs. (100 + 5 + 5.25) = Rs. 110.25 ⇒ EFFECTIVE rate = (110.25 – 100) = 10.25% Quantity 2: let the original rate be r% Then the new rate will be 2r% ⇒ (725 × r × 1)/100 + (362.50 × 2r × 1)/100 × 3 = 33.50 ⇒ (2175 + 725) r = 33.50 × 100 × 3 = 10050 ⇒ r = 10050/2900 = 3.46% ⇒ Original rate = 3.46% Quantity 3: Let the interest be r% Difference between SI – CI ⇒ [15000 × (1 + r/100)2 – 15000] – [15000 × r × 2/100] = 96 ⇒15000 × [(1 + r/100)2 – 1 – (r × 2/100)] = 96 ⇒ 15000 × [(r + 100)2 – 10000 – 200 r)/10000] = 96 ⇒ r2 = 96 × 2/3 = 64 ⇒ r = 8% Comparing all three quantities ∴ Quantity 1 > Quantity 3 > Quantity 2 |
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