(1)In a circle, a chord 1 centimetre away from the centre is 6 centime

1.	(1)In a circle, a chord 1 centimetre away from the centre is 6 centimetreslong. What is the length of a chord 2 centimetres away from the centre?
Answer» in a circle a chord 1 centimetres away answer is 3cm. because distance between chord and centre of the circle and length of chord are inversely proportional to each other hope it will help you 3 is the right answer 3 is the most valuable and correct answer it is away from2 cmso ,6-15 is the right.answer.... O is centre of the circle. DE is the chord 1 cm away from centre. CH is perpendicular on DE. ∴CH = 1 cm and DE = 6 cm FG is the chord 2 cm away from centre. CI is perpendicular on FG. ∴CI = 2 cm From centre C, CE and CG are joined. CE and CG both are radius of the circle. In ΔCHE we have, ∠CHE = 90° [∵CH is perpendicular on DE] CH = 1 cm HE = DE/2 = 3 cm [∵perpendicular drawn from centre bisects chord] In ΔCGI we have, ∠CIG = 90° [∵CI is perpendicular on FG] CI = 2 cm CG = CE = √10 cm ∴FG = 2 × IG = 2√6 cm [∵perpendicular drawn from centre bisects chord] ∴The length of the chord is = 2√6 cm

(1)In a circle, a chord 1 centimetre away from the centre is 6 centimetreslong. What is the length of a chord 2 centimetres away from the centre?

Answer»

in a circle a chord 1 centimetres away

answer is 3cm. because distance between chord and centre of the circle and length of chord are inversely proportional to each other

hope it will help you

3 is the right answer

3 is the most valuable and correct answer

it is away from2 cmso ,6-15 is the right.answer....

O is centre of the circle.

DE is the chord 1 cm away from centre. CH is perpendicular on DE.

∴CH = 1 cm and DE = 6 cm

FG is the chord 2 cm away from centre. CI is perpendicular on FG.

∴CI = 2 cm

From centre C, CE and CG are joined.

CE and CG both are radius of the circle.

In ΔCHE we have,

∠CHE = 90° [∵CH is perpendicular on DE]

CH = 1 cm

HE = DE/2 = 3 cm [∵perpendicular drawn from centre bisects chord]

In ΔCGI we have,

∠CIG = 90° [∵CI is perpendicular on FG]

CI = 2 cm

CG = CE = √10 cm

∴FG = 2 × IG = 2√6 cm [∵perpendicular drawn from centre bisects chord]

∴The length of the chord is = 2√6 cm