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1. In a sample of pure compound, Na 0.0887 mole,O 0.132 mole and C 2.65 107 atoms. The empiri-cal formula of the compound is(1) NazCO(2) Na 0Cs(3) Na00ss 132 C265 x10(4) NaCO |
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Answer» A sample of a pure compound contains 2.04g of sodium, 2.65 X 1022atoms of carbons and 0.132 mol of oxygen atoms. Find he empirical formula. Moles of Na in sample = Given mass/Molar mass of Na = 2.04 g/23 g mol-1 = 0. 088Mole of carbon1 mole C = 6. 022 x 1023atoms of CTherefore , 2.65 x 1022atoms = 2.65x 1022/6. 022 x 1023 = 0. 044Moles of oxygen = 0.132Molar ratio of Na , C and O = 0.088 : 0.044 : 0.132The simple whole number ration = 2 : 1 : 3Empirical formula of compound = Na2CO3 This is a solution to similar ques. |
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