1 kg of ice at 0^(@)C is mixed 1.5 kg of water at 45^@C[latent of fusion = 80 cal/g] Then:

1 kg of ice at 0^(@)C is mixed 1.5 kg of water at 45^@C[latent of fusi

1.	1 kg of ice at 0^(@)C is mixed 1.5 kg of water at 45^@C[latent of fusion = 80 cal/g] Then:
Answer» The TEMPERATURE of the mixture is `0^@C` Mixture CONTAINS 156.25 of ice Mixture contains 843.75 g of ice The temperature of the mixture is `15^@C` ANSWER :A::B