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1 Kg of water is pumped to a height of 1 m, the enthalpy is changed by 5 J/Kg, and work done by the motor is 25 J/Kg, assuming a system is insulated what is the change in internal energy of water?(a) 10 J(b) 25 J(c) 35 J(d) 50 J |
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Answer» Right option is (a) 10 J Explanation: ∆U = Q + W – m (∆H + ∆PE + ∆KE), => ∆U = 0 + 25*1 – 1*(5 + 10*1) = 25 – 15 = 10 J. |
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